初一合并同类项的计算题,急!

2025-12-18 03:49:41
推荐回答(3个)
回答1:

1)(3x-5y)-(6x+7y)+(9x-2y)

(2)2a-[3b-5a-(3a-5b)]

(3)(6m2n-5mn2)-6(m2n-mn2)

1)m2+(-mn)-n2+(-m2)-(-0.5n2)

(2)2(4an+2-an)-3an+(an+1-2an+1)-(8an+2+3an)

(3)化简:(x-y)2-(x-y)2-[(x-y)2-(x-y)2]

(1)a-(a-3b+4c)+3(-c+2b)

(2)(3x2-2xy+7)-(-4x2+5xy+6)

(3)2x2-{-3x+6+[4x2-(2x2-3x+2)]}

1--7(x-3)-5(2x=1)

2--m2+(-mn)-n2+(-m2)-(-0.5n2)

3--1
4--a>0,b<0,|6-5b|-|3a-2b|-|6b-1|

5--3m2n+6mn2-mn2-m2n

6--2x2-{-3x+6+[4x2-(2x2-3x+2)]}

7--a-(a-3b+4c)+3(-c+2b)

8--a-(a-3b+4c)+3(-c+2b)

9--m2+(-mn)-n2+(-m2)-(-0.5n2)

10--(3x-5y)-(6x+7y)+(9x-2y)

5a-4y+4b-5a

3a+5y-3b+5a-4y

a-2a-7+5b-3a+5y

回答2:

题目在哪?

回答3:

(x+5y)-(3y-4x)=x+5y-3y+4x

10a+6b-7a+3b-10a+10b+12a+8b

4xy-2y+3x-xy

(3x-5y)-(6x+7y)+(9x-2y)

2a-[3b-5a-(3a-5b)]