已知函数f(x)=sin(x)sin(x+π⼀2)-√3cos눀(3π+x)+1⼀2√3(x∈R)求f(x)的最小正周期

2025-05-09 19:41:58
推荐回答(1个)
回答1:

f(x)=sin(x)sin(x+π/2)-√3cos²(3π+x)+1/2√3
=sinxcosx-√3cos²x+1/2√3
=1/2sin2x-√3/2(2cos²x-1)
=1/2sin2x-√3/2cos2x
=sin(2x-π/3)
固最小正周期为T=π