解方程组(x+2)(x-2)=xy并且√(x+1)(y+4)+x+3=0

2025-05-07 06:41:06
推荐回答(3个)
回答1:

解方程组(x+2)(x-2)=xy并且√(x+1)(y+4)+x+3=0
(x+2)(x-2)=xy
x^2-4=xy
√(x+1)(y+4)+x+3=0
√(x+1)(y+4)=-(x+3)
则有x+3<=0即x<=-3
(x+1)(y+4)=(x+3)^2
xy+4x+y+4=x^2+6x+9
x^2-4+4x+y+4=x^2+6x+9
y=2x+9
x^2-4=x(2x+9)
x^2-4=2x^2+9x
x^2+9x+4=0
x=(-9±√9^2-4*1*4)/2
x=(-9±√65)/2
因为x<=-3
即x=(-9-√65)/2
y=2*(-9-√65)/2+9
y=-√65

回答2:

1xy=x²-4
则√﹙x+1﹚﹙y+4﹚=√x²+y+4x
则﹙-x-3﹚²=x²+y+4x
则y=2x+9
代入得x=-9/2-(√65)/2
y=-√652解方程组(x+2)(x-2)=xy并且√(x+1)(y+4)+x+3=0
(x+2)(x-2)=xy
x^2-4=xy
√(x+1)(y+4)+x+3=0
√(x+1)(y+4)=-(x+3)
则有x+3<=0即x<=-3
(x+1)(y+4)=(x+3)^2
xy+4x+y+4=x^2+6x+9
x^2-4+4x+y+4=x^2+6x+9
y=2x+9
x^2-4=x(2x+9)
x^2-4=2x^2+9x
x^2+9x+4=0
x=(-9±√9^2-4*1*4)/2
x=(-9±√65)/2
因为x<=-3
即x=(-9-√65)/2
y=2*(-9-√65)/2+9
y=-√65
好评偶

回答3:

x=-9/2-(√65)/2
y=-√65