Δx很小的时候,Δy=(x^2+1+Δx)^1⼀2-(x^2+1)^1⼀2约等于__

2025-12-17 04:47:21
推荐回答(1个)
回答1:

[x/√(x²+1)]*Δx
解析:
f(x)=√(x²+1)
f'(x)=x/√(x²+1)
~~~~~~~~~~~~~
Δy
≈f'(x)*Δx
=[x/√(x²+1)]*Δx